Hi,

I am new with FREERTOS and require some assistance please.

I have a 5 button system with a 2 character LCD display. I am updating the display queue in the ISR as the button are pressed. This works great but I am getting a lot of bouncings on the switches and I am looking for away in which I can debounce the buttons in the FREERTOS.

I have decreased the size of the queue to 1 and this has helped but not 100%

Is there away in doing this?

For example what if I disable the port interrupt for 10ms and then re-enable them after the interrupt occurred?

What is the correct way of doing this in the FREERTOS?

Best Regards,

Gary

I'd suggest to poll rather than use interrupts if those buttons are for human interaction only. Create a thread, poll them and use a delay (wait). Debounce by looking for two consecutive readings of the same value, and adjust the delay until they are bounce free (best is to look with a 'scope to the switch lines, but you could just try some values like 20, 50mS etc).

Unless your product is very dependent on precise timing of the buttons this will probably give you the smallest code size.

On Sep 8, 2014, at 5:25 AM, "Gary" gcgasson@users.sf.net wrote:

Hi,

I am new with FREERTOS and require some assistance please.

I have a 5 button system with a 2 character LCD display. I am updating the display queue in the ISR as the button are pressed. This works great but I am getting a lot of bouncings on the switches and I am looking for away in which I can debounce the buttons in the FREERTOS.

I have decreased the size of the queue to 1 and this has helped but not 100%

Is there away in doing this?

For example what if I disable the port interrupt for 10ms and then re-enable them after the interrupt occurred?

What is the correct way of doing this in the FREERTOS?

Best Regards,

Gary

Debouce Button Interrupt Routine

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On 09/08/2014 07:18 AM, Marc Lindahl wrote: > > I'd suggest to poll rather than use interrupts if those buttons are > for human interaction only. > Create a thread, poll them and use a delay (wait). Debounce by looking > for two consecutive readings of the same value, and adjust the delay > until they are bounce free (best is to look with a 'scope to the > switch lines, but you could just try some values like 20, 50mS etc). > > Unless your product is very dependent on precise timing of the buttons > this will probably give you the smallest code size. > >

Even though this isn't a general programming list, I'll give a freebie

uint i;

inside tick interrupt add:

i <<= 1; if(Button_Down) { i |= 1; if(!(~i & mask)) { set semaphore } }

Jerry Durand, Durand Interstellar, Inc. www.interstellar.com tel: +1 408 356-3886, USA toll free: 1 866 356-3886 Skype: jerrydurand

And if you like, here's a routine if you do not want to use an interrupt: you can call vCheckKey() from a regular task as often as you like.

Both key-press as key-release events are being filtered for dender, not for noise.

~~~~~

TimeOutt xTimeOut; BaseTypet xWaitDender = pdFALSE; BaseTypet xLastKey = 0; BaseTypet xReportedKey = 0; TickType_t xDenderTime;

BaseType_t xReadKey( void ) // Reports the current key status { // Read some i/o pin return readPort(PORTA, 4); }

void vHandleKey( BaseType_t xKeyPressed ) // Handle the key status { printf ("Pressed %lun", xKeyPressed); }

void vCheckKey( void ) { BaseType_t xKeyPressed = xReadKey( );

if( xWaitDender == pdFALSE && xReportedKey != xKeyPressed )
{
    // We were not waiting for dender,
    // so report the new key status
    xReportedKey = xKeyPressed;
    vHandleKey( xKeyPressed );
}
// Has the key value changed?
if( xLastKey != xKeyPressed )
{
    xLastKey = xKeyPressed;
    xDenderTime = DENDER_TIME;
    vTaskSetTimeOutState( &xTimeOut );
    xWaitDender = pdTRUE;
}
// Were we waiting for the dender?
else if( xWaitDender == pdTRUE )
{
    // See if the timer has expired
    if( xTaskCheckForTimeOut( &xTimeOut, &xDenderTime ) )
    {
        xWaitDender = pdFALSE;
    }
}

} ~~~~~

Regards, Hein